Difference between revisions of "Light-emitting diode"
Jump to navigation
Jump to search
(LED calculation) |
(layout fix) |
||
| Line 6: | Line 6: | ||
Example a LED with voltage drop of Uled=1.2V and a max current of I_max=0,020A (20mA) to be powered by a 5V DC source needs: | Example a LED with voltage drop of Uled=1.2V and a max current of I_max=0,020A (20mA) to be powered by a 5V DC source needs: | ||
| − | + | R = (5-1.2)/.02 = 190 ohm | |
You then connect a 190 ohm resistance in series with the LED to make it work. | You then connect a 190 ohm resistance in series with the LED to make it work. | ||
Revision as of 12:48, 27 July 2007
Light emitting diode:
The resistance required is as follows: R = (U_power - U_led) / I_max
Example a LED with voltage drop of Uled=1.2V and a max current of I_max=0,020A (20mA) to be powered by a 5V DC source needs:
R = (5-1.2)/.02 = 190 ohm
You then connect a 190 ohm resistance in series with the LED to make it work.
